When photon of energy 4.0eV strikes the surface of a metal 
, the ejected photoelectrons have maximum kinetic energy 
and deBroglie wavelength 
. The maximum kinetic energy of photoelectrons liberated from another metal 
by photon of energy 4.50eV is T B = (T A – 1.5)6V. If the DE Broglie wavelength of these photoelectrons 
, then the work function of metal B is:
Text Solution
Verified by ExpertsThe correct answer is:
D
Relation between De-Broglie wavelength and K.E. is
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